MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade:
        jee main offline problem
Resistance of 0.2 M solution of an electrolyte is 50 ohm. The specific conductance of the solution is 1.4 S m-1.
The resistance of 0.5 M solution of the same electrolyte is 280ohm. The molar conductivity of 0.5 M solution
of the electrolyte in S m2 mol-1 is:
(1) 5 × 103 (2) 5 × 102
(3) 5 × 10-4 (4) 5 × 10-3
i answered 5*10^2 which contradicts with both fiitjee and resonance keys(5*10^-4 is given as answer)

kA/L=1/R
LET L/A=X
K/x=1/R
1.4*50=X=70m-1

MOLAR CONDUCTIVITY(in si units)=k/c(in si units)
m.c.=X/RC-----(C-MOL/m3)
MC=70/(280*0.5*10^-3)
MC=0.25*2*10^3=5*10^2 IN SI UNITS
could any one debug this please
6 years ago

Answers : (1)

Sunil Kumar FP
askIITians Faculty
183 Points
							you have done correct but in the last molar conductivity=.25*2/10^3=5*10^-4
because 1M=10^-3mol/m^3 it is divided by not multiplication.

thanks and regards
sunil kumar
askIItian faculty
6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details