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Grade: 12
        
Ionic equilibrium question solve if you can.....
....
one year ago

Answers : (1)

Sahani Kumar
99 Points
							
Given : K = 4 * 10 ^-10
             ć = 0.0025        
                           B(OH)3 + H2O ----------->B(OH)4- + H+
initial number:  0.0025                              0              0    of moles 
 
Number of 
moles at
equilibrium.   (0.0025 -- α)                        α              α
 
Now we know that K = ć * (α)^2 
                    4 * 10^-10 =  0.0025 * (α)^2
                          α^2 = (4 * 10^-10)/(0.0025)
                             α = √((4 * 10^-10)/(0.0025))
                             α= 10^-6
 Now from the equation  we know that at equilibrium  H+ = α = 10^-6
We know that pH = - log[H+]
                         pH= -log[10^-6]
                         pH = 6
Regards 
Askiitian members
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one year ago
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