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`        Ionic equilibrium question solve if you can.........`
one year ago

Sahani Kumar
99 Points
```							Given : K = 4 * 10 ^-10             ć = 0.0025                                   B(OH)3 + H2O ----------->B(OH)4- + H+initial number:  0.0025                              0              0    of moles  Number of moles atequilibrium.   (0.0025 -- α)                        α              α Now we know that K = ć * (α)^2                     4 * 10^-10 =  0.0025 * (α)^2                          α^2 = (4 * 10^-10)/(0.0025)                             α = √((4 * 10^-10)/(0.0025))                             α= 10^-6 Now from the equation  we know that at equilibrium  H+ = α = 10^-6We know that pH = - log[H+]                         pH= -log[10^-6]                         pH = 6Regards Askiitian membersIf you like this answer please encourage us by approving this answer.
```
one year ago
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• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions