In what ratio should you make 0.2 molar NaNO3 and 0.1 M Ca(MO3)2 solution so that in resulting solution the concentration of Negative Ion is 50% greater than the concentration of positive ion
Madhav , 6 Years ago
Grade 12th pass
1 Answers
Sandeep Bhamoo
Last Activity: 6 Years ago
Let the ratio be K:1, then ratio of negative to positive ions is 3/2 (given) Hence (0.2K+0.2)÷ (0.2K+0.1) =3/2, K=1/2 hence their ratio is 1:2. Please do approve my answer if correct
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