0

Guest

Courses New

In the coordination compound, K4[Ni(CN)4], the oxidation state of nickel is

In the coordination compound, K4[Ni(CN)4], the oxidation state of nickel is

Grade:12

3 Answers

Gaurav
askIITians Faculty 164 Points
9 years ago
Hello Student
In the coordination compound, K4[Ni(CN)4], the oxidation state of nickel is 0.
[Ni(CN)4]4-
x + 4(-1) = -4
x = 0
Ravi Kumar
13 Points
6 years ago
The oxidation number of Ni in complex compound K4[Ni(CN)4] is equal to zero. Explanation ; Let the oxidation number of Ni is `x`Now. K4[Ni(CN)4] =1.4 + X.1 +(-1).4 =0=4 + x - 4 =0=x =0. Proved. , here K=+1,CN = - 1
Naturally Insane
27 Points
2 years ago

Let oxidation state of Nickel be x 

(1×4)+x+(4×−1)=0
4+x−4=0
 x=0
Hence, in the given compound, the oxidation state of Nickel is zero.

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More