Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

In the coordination compound, K4[Ni(CN)4], the oxidation state of nickel is

In the coordination compound, K4[Ni(CN)4], the oxidation state of nickel is

Grade:12

2 Answers

Gaurav
askIITians Faculty 164 Points
6 years ago
Hello Student
In the coordination compound, K4[Ni(CN)4], the oxidation state of nickel is 0.
[Ni(CN)4]4-
x + 4(-1) = -4
x = 0
Ravi Kumar
13 Points
3 years ago
The oxidation number of Ni in complex compound K4[Ni(CN)4] is equal to zero. Explanation ; Let the oxidation number of Ni is `x`Now. K4[Ni(CN)4] =1.4 + X.1 +(-1).4 =0=4 + x - 4 =0=x =0. Proved. , here K=+1,CN = - 1

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free