In single H atom , the electronic is excited to it's 6th orbit. The maximum number of distinct spectral lines possible , when it comes to the ground state isA)6 B)15 C)5 D)21Please explain and thank you
xxx , 5 Years ago
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1 Answers
Arun
Last Activity: 5 Years ago
generalised formula is
n=(n*-n°)(n*-n°+1)/2
Where n* is the higher level or the level from which electron jumps and n° is the lower level where electron jumps.
hence by formula, number of emission lines = 5 *6/2 = 15