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In our textbook it says that the angular momentum of an electron in an orbital is given by the formula: L=2(pi) ÷(root of l(l+1)) where l is the azimuthal quantum no. By doubts: According to quantum mechanics, you cant determine the velocity and position at the same time. If this is the case how is angular momentum even related In the formual if i calculate the angular momentum of an electon in the 3s orbital the angular momentum=0. if this is true then wont the electron fall into the nucleus.

In our textbook it says that the angular momentum of an electron in an orbital is given by the formula: L=2(pi) ÷(root of l(l+1)) where l is the azimuthal quantum no.
By doubts:
  1. According to quantum mechanics, you cant determine the velocity and position at the same time. If this is the case how is angular momentum even related
  2. In the formual if i calculate the angular momentum of an electon in the 3s orbital the angular momentum=0. if this is true then wont the electron fall into the nucleus.

Grade:11

1 Answers

yash
25 Points
7 years ago
 The reason that you have mentioned is wrong that it cannot be zero .. Yes it is zero and should be . The main fact that arises in your mind is how can a partical move if its angular momentum is zero . this where the mistake took place . your are using L=mvr which is for a particle system used in classical mechanics , but electron is not a partical it is wave in quamtum mechanics and the method to calculate are different
 

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