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In our textbook it says that the angular momentum of an electron in an orbital is given by the formula: L=2(pi) ÷(root of l(l+1)) where l is the azimuthal quantum no.By doubts:\tAccording to quantum mechanics, you cant determine the velocity and position at the same time. If this is the case how is angular momentum even related\tIn the formual if i calculate the angular momentum of an electon in the 3s orbital the angular momentum=0. if this is true then wont the electron fall into the nucleus.

S V , 8 Years ago
Grade 11
anser 1 Answers
yash

Last Activity: 8 Years ago

 The reason that you have mentioned is wrong that it cannot be zero .. Yes it is zero and should be . The main fact that arises in your mind is how can a partical move if its angular momentum is zero . this where the mistake took place . your are using L=mvr which is for a particle system used in classical mechanics , but electron is not a partical it is wave in quamtum mechanics and the method to calculate are different
 

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