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In experiment 1. 0.5gm Ag + conc.HNO3 +excess HCl = AgCl(ppt.) = 0.66gm In experiment 2 1gm Ag +Cl2 ( excess)= AgCl= 1.32gm Prove law of constant proportion

In experiment 1.      
0.5gm Ag + conc.HNO3 +excess HCl = AgCl(ppt.) = 0.66gm
 
In experiment 2
1gm Ag +Cl2 ( excess)= AgCl= 1.32gm 
Prove law of constant proportion

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