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If the maximum concentration of PbCl2 in water is 0.01 M at 298 K, Its maximum concentration in 01 M NaCl will be:- a.4*10^-4 b.4*10^-2

If the maximum concentration of PbCl2 in water is 0.01 M at 298 K, Its maximum concentration in 01 M NaCl will be:-
a.4*10^-4      b.4*10^-2

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1 Answers

Arun
25750 Points
5 years ago
Dear Tanusri
 
I am getting my answer as 4 * 10^-4
 
Hence option A is correct
 
Regards
Arun (askIITians forum expert)

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