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Grade: 12th pass
        
if the curvees x^2/R+y^2/4=1 and y^2=16x intersect at right angles then value of ‘R’
one month ago

Answers : (1)

Vikas TU
8825 Points
							
Let Both cut at angle (x1,y1)
x^2/R+y^2/4=1
so , on differenciating 
2x / R + 2y*y'/4 = 0
y' = -x/R *4/y 
Diiferenciating another curve 
2y *y' = 16 
y' = 8/y 
Both solpe is perpendicular 
-x1/R * 4/y1 * 8/y1  = -1 
y1 ^2 =16x1 
Put this value 
32 /16R = 1 
R = 2 
one month ago
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