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Grade: 12th pass
        If the concentration of OH- ions in the reaction Fe(OH)3 (s) Fe+3 (aq.) + 3OH-(aq.) is decreased by 1/4 times, then equilibrium concen tration of Fe+3 will increase by
3 years ago

Answers : (2)

Vikas TU
11769 Points
							Fe(OH)3 (s) =============> Fe+3 (aq.) + 3OH-(aq.) 
The eqm/. constant would always attain/constant at eqm.
Hence,
K = (OH-)^3*(Fe3+)/(Fe(OH)3)
Now here,
Fe^3+ is inversely proportional to the cube of the conc. of OH-.
Hence,
Fe3+ = k oh-^3
Fe3+’ = k(oh-/3)^3
Fe3+’ = Fe3+/64
hence it increased by 1/64th of previous Fe3+ concentration. 
3 years ago
Kushagra Madhukar
askIITians Faculty
605 Points
							
Dear student,
Please find the solution to your problem.
 
Fe(OH)3 (s) → Fe+3 (aq.) + 3OH-(aq.)
The eqm. constant would remain constant
Hence,
K = [OH-]3[Fe3+]/[Fe(OH)3]
Now here,
Fe3+ is inversely proportional to the cube of the conc. of OH-.
Hence,
Fe3+ = c [OH-]–3
Fe3+’ = c ([OH-]/4)–3
Fe3+’ = 64c [OH-]–3
Fe3+’ = 64 Fe3+
hence it increased by 64th of previous Fe3+ concentration. 
 
Thanks and regards,
Kushagra
6 days ago
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