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Grade:

                        

If the concentration of CrO4^2- ion in a saturated solution of silver chromate will be 2*10^-4 M, solubility product of silver chromate will be:- a.4*10^-8 b.32*10^-12

2 years ago

Answers : (1)

Arun
24742 Points
							
Ag2CrO4(s) ===⇒ 2Ag+ + (CrO4)-2 
[Ag+] = 2(2 x 10^-4) = 4 x 10^-4
[CrO4-2] = 2 x 10^-4 
Ksp = [Ag+]^2[CrO4-2] 
Ksp = (4 x 10^-4)^2(2 x 10^-4) 
Ksp = 32 x 10^-12
Hence option B is correct
2 years ago
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