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Grade: 12

                        

If pKb for fluoride ion at 25 degree celsius is 10.83,the ionisation constant of hydrofluoric acid in water at this temperature is???

If pKb for fluoride ion at 25 degree celsius is 10.83,the ionisation constant of hydrofluoric acid in water at this temperature is???

4 years ago

Answers : (2)

Soumika Hallder
11 Points
							
pKb = 10.83     kb = 10^-10.83 = 1.48*10^-11
HF + H2O =  F- + H3O+
Ka * Kb = Kw
Ka = Kw/Kb = 10^-14/1.48*10^-11 = 6.76 * 10^-4
3 years ago
ankit singh
askIITians Faculty
614 Points
							
Kb = 10.83     kb = 10^-10.83 = 1.48*10^-11
HF + H2O =  F- + H3O+
Ka * Kb = Kw
Ka = Kw/Kb = 10^-14/1.48*10^-11 = 6.76 * 10^-4
7 months ago
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