Grade 12Physical ChemistryIf pKb for fluoride ion at 25 degree celsius is 10.83,the ionisation constant of hydrofluoric acid in water at this temperature is??? Ayush Chaturvedi 9 Years agoGrade 12
Soumika Hallder8 Years agopKb = 10.83 kb = 10^-10.83 = 1.48*10^-11HF + H2O = F- + H3O+Ka * Kb = KwKa = Kw/Kb = 10^-14/1.48*10^-11 = 6.76 * 10^-4
ankit singh5 Years agoKb = 10.83 kb = 10^-10.83 = 1.48*10^-11HF + H2O = F- + H3O+Ka * Kb = KwKa = Kw/Kb = 10^-14/1.48*10^-11 = 6.76 * 10^-4