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Grade: 12th pass
        
 If NaCl is doped with 10–3 mole of BaCl2. What is the concentration of cationic vacancies?
3 months ago

Answers : (2)

Arun
23386 Points
							

NaCl is doped with 10-3 mole % of SrCl2.This means, 100 moles of NaCl are doped with 10-3 moles of SrCl2.

Therefore, 1mole of NaCl is doped with 10-3 /100 = 10-5 moles of SrCl2 or 10-5 moles of Sr2+.

Now,

One Sr2+ ion create one cation vacancy.

Therefore, no. of cation vacancies created by 10-5 moles Sr2+

= 10-5 moles/mole of NaCl

= 10-5 x 6.022 x 1023 / mole of NaCl

= 6.022 x 1018/ mole of NaCl

3 months ago
Vikas TU
9810 Points
							
Dear student 
Kindly follow the below Link For your ans 
Hope this will help. 
Good Luck 
Cheers 
3 months ago
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