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```
if 4 grams of sodium hydroxide is dissolved in 36 grams of water. the solution has the density of 1 gram per ml. find the mole fraction of sodium hydroxide along with molality

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2 years ago

```							number of moles in 4 g NaOH= wt in gms/molwt=4/40=0.1number of moles in 36 g H2O=wt in gms/mol wt=36/18=2total no of moles=0.1+2.0=2.1mole fraction o​f naoh=0.1/2.1=0.04mole fraction of h2o=20/21=0.95 Density = Mass/ Volume Volume = Mass/DensityVolume (solution) = mass of solution/Density of solution                              = 40 g / 1g ml                              = 40 g Molarity = No . Moles of Solute x 1000 / Volume of the Solution (Into 1000 because Density is in g/ml)               = .1 x 1000/40                = 10/4                = 2.5 M
```
2 years ago
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