Kushagra Madhukar
Last Activity: 4 Years ago
Dear student,
Please find the solution to your problem below.
There seems to be some missing data from your question.
Taking Vapour pressure of H2O at 300 K = 3170Pa
Volume of water added = 10-4 dm3
Now, The volume occupied by water molecules in vapour phase is (1 – 10-4) dm3, that is approximately 1
Now, PvapV = nH2ORT
3170 x 1 x 10-3 = nH2O x 8.314 x 300
or, nH2O = 3170 x 10-3/(8.314 x 300) = 1.27 x 10-3
Thanks and regards,
Kushagra