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if 10- dm 3 - of water is introduced into a 1.0 dm 3 - flask at 300 K, how many moles of water are in in the vapour phase when equilibrium is established ?

if 10- dm 3 - of water is introduced into a 1.0 dm 3 - flask at 300 K, how many moles of water are in in
the vapour phase when equilibrium is established ?

Grade:12

2 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
6 years ago
The volume occupied by water molecules in vapour phase is (1 – 10-4) dm3, that is approximately 1 dm3.204-1063_chemistry_clip_image009.gif
Kushagra Madhukar
askIITians Faculty 629 Points
10 months ago
Dear student,
Please find the solution to your problem below.
 
There seems to be some missing data from your question.
Taking Vapour pressure of H2​O at 300 K = 3170Pa
Volume of water added = 10-4 dm3
Now, The volume occupied by water molecules in vapour phase is (1 – 10-4) dm3, that is approximately 1
Now, PvapV = nH2ORT
3170 x 1 x 10-3 = nH2O x 8.314 x 300
or, nH2O = 3170 x 10-3/(8.314 x 300) = 1.27 x 10-3
 
Thanks and regards,
Kushagra

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