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if 10- dm 3 - of water is introduced into a 1.0 dm 3 - flask at 300 K, how many moles of water are in in the vapour phase when equilibrium is established ?

if 10- dm 3 - of water is introduced into a 1.0 dm 3 - flask at 300 K, how many moles of water are in in
the vapour phase when equilibrium is established ?

Grade:12

2 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
8 years ago
The volume occupied by water molecules in vapour phase is (1 – 10-4) dm3, that is approximately 1 dm3.204-1063_chemistry_clip_image009.gif
Kushagra Madhukar
askIITians Faculty 629 Points
2 years ago
Dear student,
Please find the solution to your problem below.
 
There seems to be some missing data from your question.
Taking Vapour pressure of H2​O at 300 K = 3170Pa
Volume of water added = 10-4 dm3
Now, The volume occupied by water molecules in vapour phase is (1 – 10-4) dm3, that is approximately 1
Now, PvapV = nH2ORT
3170 x 1 x 10-3 = nH2O x 8.314 x 300
or, nH2O = 3170 x 10-3/(8.314 x 300) = 1.27 x 10-3
 
Thanks and regards,
Kushagra

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