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If λ0 is the threshold wavelength for photoelectric emission, λ is the wavelength of light falling on the surface of metal and m is the mass of electron, then find the de Broglie wavelength of emitted electron.

shrimanti , 8 Years ago
Grade 11
anser 1 Answers
Vikas TU
 λ =h/mv 
Where λ= wavelength of electron, 
h= planck's consistent 
m=mass of the electron 
v= speed of the electron 
however, v= λ0*1/T 
where T= time period.
Last Activity: 8 Years ago
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