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I need the answer to the question please help me with the question
22.4 Litre gas contains 1 mole at 1 atm & 273K ( STP )22.4 Litre gas contains 5 mole at 5 atm & 273K ( STP )4.48 Litre gas C(g) at 5 atm contains = (4.48/22.4)*5=1 mole3A(s) -----> 3B(s) + C(g)3 mole 3 mole + 1 mole Total mole of A(s) = 10 ( given) ;Moles of A(s) remaining for 2nd Rx = 10-3 = 7A(s)----> 5D(s)7 mole 35 molResidue means solid (s); Total residue= B(s)+D(s)= 3+35=38 moles
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