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Grade: 10

                        

I need the answer to the question please help me with the question

2 years ago

Answers : (1)

Navin Rai
16 Points
							
22.4 Litre gas contains 1 mole at 1 atm & 273K ( STP )
22.4 Litre gas contains 5 mole at 5 atm & 273K ( STP )
4.48 Litre gas C(g) at 5 atm contains = (4.48/22.4)*5=1 mole
3A(s) -----> 3B(s)  + C(g)
3 mole       3 mole  + 1 mole     
Total mole of A(s) = 10  ( given) ;
Moles of A(s) remaining for 2nd Rx = 10-3 = 7
A(s)----> 5D(s)
7 mole     35 mol
Residue means solid (s);    Total residue= B(s)+D(s)= 3+35=38 moles
2 years ago
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