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i am not clear with my basics.eg. 1 question like we have to find the n-factor of a compound.eg KMnO4 so my sir writes KMnO4 gives Mn with a 2+ charge in acidic medium so i do not understand what is this Mn charge 2+.is it an ion or does it represents a part of compound in which we are working.if so then does every compound gives Mn charge 2+ when KMnO4 reacts. in general my main doubt is how do they write the rigth hand product side

i am not clear with my basics.eg. 1 question
like we have to find the n-factor of a compound.eg KMnO4
so my sir writes
KMnO4 gives Mn with a 2+ charge in acidic medium
so i do not understand what is this Mn charge 2+.is it an ion or does it represents a part of compound in which we are working.if so then does every compound gives Mn charge 2+ when KMnO4 reacts.
in general my main doubt is how do they write the rigth hand product side

Grade:12th pass

1 Answers

Vikas TU
14149 Points
7 years ago
Dear Shashwat,
Your doubt is genuine.
KMnO4 greatly reduces to Mn2+
And therefore, valence factor becomes = > 7 – 2 = 5.
Now remember this mole concept – 2.
Here we are not doing that balancing the eqns. or writing total product formed as we are not interested here to write that.
Because all the moles – molarity – volume or titration problems can be solved by using valence factor here simply.
So only the valency is required for metal atom to calculate the valence factor.
.
And the main formulae to calculate the moles is:
moles x valence factor = moles x valence factor.
U need to understand this.
 
 

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