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        How much volume of oxygen at STP in litres is required to burn 4 g of methane gas completely?
2 years ago

Arun
23013 Points
							Dear student The balanced chemical equation for combustion of methane is given as:​CH4  +  2O2  →  CO2  +  2H2O So 1 mole of CH4 requires 2 moles of O2 for complete combustion.Molar mass of methane = 16 g.Number of moles of methane in 4 g sample = 4 g/16 g = 1/4 mole.If ​1 mole of CH4 requires 2 moles of O2 for complete combustion.Therefore 1/4 ​mole of CH4 will requires = 1/4 ×2 moles of O2 = 0.5 mol of O2 for complete combustion.1 mole of all the gases occupy 22.4 L at STPTherefore 0.5 mole will occpy 22.4 L × 0.5 mol = 11.2 LSo 11.2 L of O2 is required for complete combustion of 4 g CH4. RegardsArun (askIITians forum expert)

2 years ago
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