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Charge on Al in Al2O32Al + 3O = 0 Oxygen has –2 2Al +3(–2) = 0 Al = 3 Change transfer n = 3 Charge required for 1 mol of Al = 3FNumber of moles of Al = 40 /27 = 1.48
The electricity required to produce 1.48 mol of Al = 1.48 × 3 F = 4.44 F
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