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how manyy moles of mg3[po4]2will contain 0.25 mole of oxygen atom?

how manyy moles of mg3[po4]2will contain 0.25 mole of oxygen atom?

Grade:12

1 Answers

Vignesh M
42 Points
7 years ago
1 mole of mg3[po4]2 = 8 moles of O 1 Mole of O = mg3[po4]2 / 8 0.25 Mole of O = mg3[po4]2 / 8*4

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