Grade 11Mechanics

How many moles of P4 can be produced by reaction of 0.1 moles of Ca5(PO4)3F,0.36 moles SiO2 and 0.9 moles C according to the given reaction-
4Ca5(PO4)3F+18SiO2+30C GIVES 3P4+2CaF2+18CaSiO3
+30CO

MANAS GOEL

8 Years agoGrade 11

1 Answer

HIMANSHU SHEKHAR DAS

8 Years ago

in this question let us find the limiting reagent first.

let us assume that Ca₅(PO₄)₃F is consumed fully and the other 2 remains

so according to the balanced chemical equation, 4 moles of Ca₅(PO₄)₃F will react with 18 moles of SiO₂

so 0.1 moles react with 0.45 moles of SiO₂, while the given amount is 0.36 moles.

So Ca₅(PO₄)₃F cannot be the limiting reagent.

now let us go to SiO₂ , here according to balanced chemical equation, 18 moles react with 4 moles of Ca₅(PO₄)₃F.

so 0.36 moles of SiO₂ will react with 0.08 moles which is less than the provided amount.

again 18 moles of SiO₂ will react with 30 moles of C.

so 0.36 moles of SiO₂ will react with 0.6 moles of C, which is also more than the provided amount.

so SiO₂ is the limiting reagent.

now have to find the amount of product according to limiting reagent as the reaction will not carried forward after any reactant gets finished.

the the amount of any product produced can be found by balancing with the amount consumed of the limiting reagent.

so 18 moles of SiO₂ will react to give 3 moles of P₄

so 0.36 moles of will react to give 0.06 moles P_4.

so 0.06 moles of P₄ will be produced.(ans)

thanks

hope it helps !!!

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How many moles of P4 can be produced by reaction of 0.1 moles of Ca5(PO4)3F,0.36 moles SiO2 and 0.9 moles C according to the given reaction-4Ca5(PO4)3F+18SiO2+30C GIVES 3P4+2CaF2+18CaSiO3+30CO

MANAS GOEL

1 Answer

HIMANSHU SHEKHAR DAS

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