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how many grams of 90% of pure Na2SO4 can be produced from 250g of 95% pure Na2SO4?solnis given as:250x95/100 gm of Nacl = 4.05 mol of Nacl= 4.05 mol of Na2SO4= !/2x4.05x142x100/90 g Na2SO4 or320g of Na2So4HOW TO CALCULATE IT? wHAT IS THE METHOD FOR 90% OF Na2SO4?

SANIKA , 10 Years ago
Grade 12th Pass
anser 1 Answers
Sunil Kumar FP

Last Activity: 10 Years ago

for this its very easy to calculate wirh the concept of equivalent weight.

for reaction A+B=C+D,equivalent of A=B=C=D,where equivalent=weight/equivalent wt
now equivalent weight of nacl=58.5,equivalentweightof na2so4=71(molecularwt/valency)142/2

Atp,.equivalent of nacl=equivalent of na2so4
wt/eqwt nacl=wt/eq wt na2so4
250×.95/58.5=x× .9/71
x=320 gm

sunil kumar
thanks and regards
askiitian faculty


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