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gold crystallises in ccp structure. the total no. of voids present in 197g of gold will b 1.197 * avagadro no. 2 * ,, 3 * ,, 4 * 197*,,

gold crystallises in ccp structure. the total no. of voids present in 197g of gold will b
1.197 * avagadro no.
  1. 2 * ,,
  2. 3 * ,,
  3. 4 * 197*,,

Grade:12

3 Answers

shubham sharda
360 Points
8 years ago
There are total of 3N voids in ccp structure. The amount give in the question is 197g which is 1 mole of gold. So, to. no of holes in 1 mole of gold in ccp structure would be 3*Avogadro no.
Hope i helped.
Geetika
11 Points
7 years ago
The no. of voids = octahedral voids + tetrahedral voids 
=>No.of octahedral voids in one mole of gold is= Avagadro no.x1 (since no of octahedral voids are equal to no.of unp atoms present in the sample )
=>No.of of tetrahedral voids in one mole of gold is= Avagadro no. x2(since the no. of octahedral voids is twice the no. of of atoms present in the sample)
Therefore,    The total no. Of voids is=1*avagardro no. +2*avagadro no. =3*avagadro no. 
Reetu
19 Points
6 years ago
Given mass=197gMoles=197/197=1No. of atoms =1*avegadro no. Total no. of voids in ccp structure=3NTotal no. of voids in 197 g =3*avagadro no.

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