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        Glucose is added to 1 litre water to such an extent that delTf/Kf becomes equal to 1/1000 the wt. of glucose added is:a.18g         b.0.18g
4 months ago

Amol Shegokar
13 Points
							Depression in freezing point $\Delta Tf$ = m . Kf $\therefore \Delta Tf/Kf = m$let ‘x’ g of glucose is added in 1 L of water (1kg of water as density is 1g/cc for water) $m = molality = \frac{moles of solute}{kg of solvent} = \frac{x/180}{1}$mol. wt of glucose = 180 and moles = wt / mol wt.$\therefore \frac{x}{180} = \frac{1}{1000}$$x = 0.18 g of glucose$

4 months ago
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