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From 320mg of O2 6.023×10^20 molecules are removed then the number of moles remained From 320mg of O2 6.023×10^20 molecules are removed then the number of moles remained
Oxygen is a diatomic molecule= O2 = (16x2) = 32 g in one mole As we know, 32 g of O2 =1 mol = 6.023x1023 Therefore, 320mg = 0.32g = 0.01 mol = 6.023x1021 From this, 6.023x1020 moles are removed = 0.001 moles Therefore remaining moles are 0.01-0.001 =0.009 moles remain
Oxygen is a diatomic molecule= O2 = (16x2) = 32 g in one mole
As we know,
32 g of O2 =1 mol = 6.023x1023
Therefore, 320mg = 0.32g = 0.01 mol = 6.023x1021
From this, 6.023x1020 moles are removed = 0.001 moles
Therefore remaining moles are 0.01-0.001 =0.009 moles remain
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