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Physical Chemistry> For the reaction PCl3(g)+ Cl2(g)= PCl5(g)...

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For the reaction PCl3(g)+ Cl2(g)= PCl5(g), the value of Kc at 250 degree celsius is 26. Then value of Kp at this temperature is(a) 0.61(b) 0.57(c) 0.83(d) 0.46

Josi dines , 7 Years ago

Grade 12th pass

2 Answers

Shivam

Last Activity: 7 Years ago

(a) 0.61Kp = Kc× (RT)^∆n∆n=(no of moles of gaseous products - no of moles of gaseous reactants)Therefore, ∆n = 1-2= (-1)Now, Kc=26, R=0.0821, T= 250+273.15=523.15KHence, Kp= 26×(RT)^ -1=26/RT = 26/(0.0821×523.15) = 0.61

Kushagra Madhukar

Last Activity: 4 Years ago

Dear student,
Please find the attached solution to the problem.

Kp = Kc×(RT)^∆ng
∆n_g = no of moles of gaseous products - no of moles of gaseous reactants
Therefore, ∆n_g = 1-2 = (-1)
Now, Kc = 26, R = 0.0821, T = 250+273.15 = 523.15K
Hence, Kp = 26×(RT)-1 = 26/RT = 26/(0.0821×523.15) = 0.61

Hence a) is the correct option.

Hope it helps.

Thanks and regards,

Kushagra

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