Shivam
Last Activity: 8 Years ago
(a) 0.61Kp = Kc× (RT)^∆n∆n=(no of moles of gaseous products - no of moles of gaseous reactants)Therefore, ∆n = 1-2= (-1)Now, Kc=26, R=0.0821, T= 250+273.15=523.15KHence, Kp= 26×(RT)^ -1=26/RT = 26/(0.0821×523.15) = 0.61