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For the reaction H2(g) +Cl2(g) =2HCl(g) if 20 ml of H2 gas and 30ml of Cl2 gas are taken in a container then what is the volume of gas present in the container after the reaction
For the reaction H2(g) +Cl2(g) =2HCl(g) if 20 ml of H2 gas and 30ml of Cl2 gas are taken in a container then what is  the volume of gas present in the container after the reaction


3 years ago

sam
22 Points
							I will do this by Mole concept as it will give conceptual clarity. we know that 1 mole of any gas occupies 22.4 L of volume at STP. in this reaction 1 millimole of H2 gas is required to react with 1 millimole of Cl2 gas  to produce 2 millimoles of HCl gasbut since we do not have 1 millimole H2 , H2  will be the limiting regent.Thus millimoles of H2 = 20/22.4thus equal millimoles of Cl2 are required = 20/22.4therefore millimoles of HCl formed are 2$\fn_cm \times$ 20/22.4 thus volume of HCl formed = 2$\fn_cm \times$ 20/22.4 $\fn_cm \times$ 22.4 (as 1 mole of any gas takes 22.4 L of volume at STP)But Cl2 gas is also left in some quantity. That quantity is (30-20) ml = 10 mlVolume of gas present in the container is 40 ml of HCl and 10 ml of CL2 Thus total volume og gas is 50 ml

3 years ago
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