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For a reaction A + 3B gives 2C + D initial mole of A is twice that of B. If at equilibrium moles of B and C are equal, then percent of B reacted is ?

```
4 years ago

Vikas TU
14146 Points
```							                   A + 3B --------> 2C + D t=0           2a     a                 0        0t=t              2a-x   a-x               2x        xNow given,a-x = 2x = > a = 3x = > x = a/3.[B] = 2a/3[A] = 5a/3% of B reacted is: => a/3a * 100 = 33.33 %
```
4 years ago
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