For a reaction A + 3B gives 2C + D initial mole of A is twice that of B. If at equilibrium moles of B and C are equal, then percent of B reacted is ?

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Vikas TU · Answer

A + 3B --------> 2C + D t=0 2a a 0 0 t=t 2a-x a-x 2x x Now given, a-x = 2x = > a = 3x = > x = a/3. [B] = 2a/3 [A] = 5a/3 % of B reacted is: => a/3a * 100 = 33.33 %

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For a reaction A + 3B gives 2C + D initial mole of A is twice that of B. If at equilibrium moles of B and C are equal, then percent of B reacted is ?

For a reaction A + 3B gives 2C + D initial mole of A is twice that of B. If at equilibrium moles of B and C are equal, then percent of B reacted is ?

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For a reaction A + 3B gives 2C + D initial mole of A is twice that of B. If at equilibrium moles of B and C are equal, then percent of B reacted is ?

For a reaction A + 3B gives 2C + D initial mole of A is twice that of B. If at equilibrium moles of B and C are equal, then percent of B reacted is ?

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