For 10 minutes each, at 27 degree celsius,from two identical holes nitrogen and an unknown gas are leaked into a common vessel of 3L capacity.The resulting pressure is 4.18 bar and its mixture contains 0.4 moles of nitrogen.What is the molar mass of the unknown gas?

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Agrata Singh · Answer

I

Agrata Singh · Answer

I am attaching an image of the solution. I calculated the no of moles of each gas in the container and then compared to find the respective rate of diffusion of gases. Thereafter I applied the diffusion-molar mass relation. Hope it helps.

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For 10 minutes each, at 27 degree celsius,from two identical holes nitrogen and an unknown gas are leaked into a common vessel of 3L capacity.The resulting pressure is 4.18 bar and its mixture contains 0.4 moles of nitrogen.What is the molar mass of the unknown gas?

For 10 minutes each, at 27 degree celsius,from two identical holes nitrogen and an unknown gas are leaked into a common vessel of 3L capacity.The resulting pressure is 4.18 bar and its mixture contains 0.4 moles of nitrogen.What is the molar mass of the unknown gas?

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For 10 minutes each, at 27 degree celsius,from two identical holes nitrogen and an unknown gas are leaked into a common vessel of 3L capacity.The resulting pressure is 4.18 bar and its mixture contains 0.4 moles of nitrogen.What is the molar mass of the unknown gas?

For 10 minutes each, at 27 degree celsius,from two identical holes nitrogen and an unknown gas are leaked into a common vessel of 3L capacity.The resulting pressure is 4.18 bar and its mixture contains 0.4 moles of nitrogen.What is the molar mass of the unknown gas?

2 Answers

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