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Find the volume of 5 molal H2 SO4 solution(d=1.2g / ml) which should be added to 100ml of 98% H2 SO4 solution (d=1.8 g/ ml) in order to obtain 10 molal H2SO4 solution.
Let v litre 5 molal H2SO4 is required5 molal H2SO4 = 5moles of H2SO4 1 kg of solvent=5moles of H2SO4 {density = mass/volume 1/1.2 litre of solvent Molarity=. No. Of moles Volume=6 molar solutionNow if we take v litre of this solutionThen, no. Of moles of H2SO4 in v litre=6vFor II solution98% H2SO4 =98ml H2SO4 in 100 mlWt. Of H2SO4 =98*1.8Moles =98*1.8/98=1.8Now if we mix both solutions then total moles=1.8+6vTotal volume Of solvent=0.1+v10= 6v+1.8 0.1+vV=0.2litre
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