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Grade: 12th pass
        
Equivalent conductivity of BaCl2,H2SO4 and HCl are x1, x2, x3 Scm2eq-1 respectively at infinite dilution. If conductivity of saturated BaSO4 solution is x Scm-1, then Ksp of BaSO4 is?
one year ago

Answers : (1)

pulkit srivastav
19 Points
							
It’s a pretty simple and basic concept oriented question.
But no doubt does confuse people for a long time especially regarding the concept of equivalent and molar conductivity question.
 
the answer may not be exactly apt but should help you enough to get the concept behind it.
 
ANSWER
 
∂= lambda= equivalent conductance ( delta knot)
 
∂BaSO4 = ∂BaCl2 + ∂H2SO4 - ∂2HCl
             = x1 + x2 + – 2x3
∂BaSO4 = 1000 * sp. conductance.
               solubility( in saturated sol.)
 
x1 + x2 – 2x3 = 1000y/ solubility
 
=> solubility BaSO4 = 1000y N                [ N= M/ z factor = M/2]
                                x1+x2-2x3
 
                              = 1000y M
                                 x1+x2-2x3
 
       BaSO4 ------> Ba 2+ + SO4 2- 
ksp (BaSO4)= [Ba 2+][SO4 2-] M^2
                   = 10^6 y^2
                   4(x1+x2-2x3)^2
 
Hope this helps you and wish you luck ^,^
 
 
 
one year ago
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