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Grade: 12th pass
Equivalent conductivity of BaCl2,H2SO4 and HCl are x1, x2, x3 Scm2eq-1 respectively at infinite dilution. If conductivity of saturated BaSO4 solution is x Scm-1, then Ksp of BaSO4 is?
2 years ago

Answers : (1)

pulkit srivastav
19 Points
It’s a pretty simple and basic concept oriented question.
But no doubt does confuse people for a long time especially regarding the concept of equivalent and molar conductivity question.
the answer may not be exactly apt but should help you enough to get the concept behind it.
∂= lambda= equivalent conductance ( delta knot)
∂BaSO4 = ∂BaCl2 + ∂H2SO4 - ∂2HCl
             = x1 + x2 + – 2x3
∂BaSO4 = 1000 * sp. conductance.
               solubility( in saturated sol.)
x1 + x2 – 2x3 = 1000y/ solubility
=> solubility BaSO4 = 1000y N                [ N= M/ z factor = M/2]
                              = 1000y M
       BaSO4 ------> Ba 2+ + SO4 2- 
ksp (BaSO4)= [Ba 2+][SO4 2-] M^2
                   = 10^6 y^2
Hope this helps you and wish you luck ^,^
one year ago
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