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Grade: 12th pass
        
Each of the two platinum electrodes having area 64mm​of a conductivity cell are separated by 8 mm. The resistance of the cell containing 7.5×10−3 M KCl solution at 298 K is 1250 ohm. Calcualte:
1.   Cell constant
2.   Conductivity and
3. Molar conductivity
one year ago

Answers : (1)

Arun
23341 Points
							
Dear student
 
Cell constant = l/A 
 
Conductivity = l/RA
 
Put the valiws and you will get the answers
 
 
Regards
Arun
one year ago
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