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Grade: 12th pass

                        

Draw diagram of ∆G⁰ vs. T for the following reactions: 4Cu (s) + O2(g) = Cu2O(s) ∆G⁰= – 338900 -14.2T lnT + 247 T Joule 4Cu (l) + O2(g) = Cu2O(s) ∆G⁰ = – 390800 - 14.2T lnT + 285.3 T Joule Calculate the melting point of the copper from ∆G⁰ vs. T plot.

Draw diagram of ∆G⁰ vs. T for the following reactions:
4Cu (s) + O2(g) = Cu2O(s)
∆G⁰= – 338900 -14.2T lnT + 247 T Joule  
4Cu (l) + O2(g) = Cu2O(s)
∆G⁰ = – 390800 - 14.2T lnT + 285.3 T Joule
Calculate the melting point of the copper from ∆G⁰ vs. T plot.

2 months ago

Answers : (1)

Govind Sharma
166 Points
							
The Part Related To This Question Is Removed From JEE Syllabus.
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24 days ago
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