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Correct set of four quantum numbers for the valence (outermost) electron of rubidium (Z = 37) a. 5, 0, 0, + 1/2 b. 5, 1, 0, + 1/2 c. 5, 1, 1, + 1/2 d. 6, 0, 0, + 1/2

Correct set of four quantum numbers for the valence (outermost) electron of rubidium (Z = 37)
a. 5, 0, 0, + 1/2
b. 5, 1, 0, + 1/2
c. 5, 1, 1, + 1/2
d. 6, 0, 0, + 1/2

Grade:11

2 Answers

Kevin Nash
askIITians Faculty 332 Points
9 years ago
The valence shell configuration of rubidium (Rb) is [Kr] 5s1 n = 5, l = 0, m = 0, s = + 1/2 or - 1/2
jyoti bhatia
202 Points
5 years ago
 Electronic configuration of Rb = 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s1
Check that there are 37 electrons.
Thus, 
Principal quantum number, n = 5

Azimuthal quantum number, l = 0 (since for s orbital l = 0) 

Magnetic quantum number, m = 0 (since for l = 0, there is only one m value i.e. 0) 

Spin quantum number, s = +½ or -½ (there is only one electron and it can have clockwise or anticlockwise spins) 

Conclusion: 

The correct set of quantum numbers will be: 5, 0, 0, +½ or -½. Therefore correct option is 1.

 

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