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Grade: 11
        Correct set of four quantum numbers for the valence (outermost) electron of rubidium (Z = 37)

a. 5, 0, 0, + 1/2
b. 5, 1, 0, + 1/2
c. 5, 1, 1, + 1/2
d. 6, 0, 0, + 1/2
5 years ago

Answers : (2)

Kevin Nash
askIITians Faculty
332 Points
							The valence shell configuration of rubidium (Rb) is
[Kr] 5s1  n = 5, l = 0, m = 0, s = + 1/2 or -  1/2

						
5 years ago
dolly bhatia
200 Points
							
 Electronic configuration of Rb = 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s1
Check that there are 37 electrons.
Thus, 
Principal quantum number, n = 5

Azimuthal quantum number, l = 0 (since for s orbital l = 0) 

Magnetic quantum number, m = 0 (since for l = 0, there is only one m value i.e. 0) 

Spin quantum number, s = +½ or -½ (there is only one electron and it can have clockwise or anticlockwise spins) 

Conclusion: 

The correct set of quantum numbers will be: 5, 0, 0, +½ or -½. Therefore correct option is 1.

 
one year ago
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