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Consider the reaction: Cr2O72– + 14H+ + 6e– ? 2Cr3+ + 7H2O What is the quantity of electricity in coulombs needed to reduce 1 mol of Cr2O72–?

Consider the reaction: Cr2O72– + 14H+ + 6e– ? 2Cr3+ + 7H2O What is the quantity of electricity in coulombs needed to reduce 1 mol of Cr2O72–?

Grade:8

4 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
7 years ago
the quantity of electricity in coulombs needed to reduce 1 mol of Cr2O72-204-1209_Wed Aug 20 15-34-52.jpg
shashidhar
15 Points
2 years ago
2x-14=-2
2x=12
x=6
~6×96500=579000C is the charge required  to reduce the 1 mol of cr2o72-, the amount of charge is required to reduction is 579000C
Kushagra Madhukar
askIITians Faculty 629 Points
one year ago
Hello student
As mentioned, the balanced chemical reaction is-
Cr2O72– + 14H+ + 6e→ 2Cr3+ + 7H2O
As per the reaction, 1 mole of Cr2O72- is reduced by 6 moles of electrons = 6 Faraday
= 6 x 96500 C
= 579000 C
Hope it helps.
Regards,
Kushagra
Yash Chourasiya
askIITians Faculty 256 Points
one year ago
Dear Student

The balanced chemical reaction is-
Cr2O72–+ 14H++ 6e → 2Cr3++ 7H2O
As per the reaction, 1 mole of Cr2O72-is reduced by 6 moles of electrons = 6 Faraday
= 6 x 96500 C
=579000 C

I hope this answer will help you.
Thanks & Regards
Yash Chourasiya

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