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Grade 12th passPhysical Chemistry

Compare the difference between ∆H and ∆U for the following changes..1.1mol ice and 1mol water at 273k and 1atmosphere..2.1mol water to 1mol steam at 373k and 1atmosphere..the molar volume of ice and water at 273k are .0196l/mol and .0180l/mol..the molar volumes of water and steam at 373k are .0188l/mol and 30.61l/mol respectively

Prattusha Chakraborty

7 Years agoGrade 12th pass

1 Answer

Arun

6 Years ago

Since heat is absorbed here at constant pressure so ΔH=1440 calories

ΔU can be calculated by using the formula ΔU=ΔH−PΔV

P=1atm, ΔV=0.0196L−0.180L=0.0016L

P ΔV=1∗0.0016=0.0016Latm=0.0016∗24.217calories. (1Latm=24.217 calories)

So ΔU=1440cal−0.0016∗24.217cal≈1439.96calories .There is negligible work done here.

so you can write ΔH≈ΔU.

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