[email protected]

India's First Online IIT-JEE & NEET Coaching Platform - Trusted Since 2006

+91 87964 74404

Grade 12th passPhysical Chemistry

Compare the difference between ∆H and ∆U for the following changes..1.1mol ice and 1mol water at 273k and 1atmosphere..2.1mol water to 1mol steam at 373k and 1atmosphere..the molar volume of ice and water at 273k are .0196l/mol and .0180l/mol..the molar volumes of water and steam at 373k are .0188l/mol and 30.61l/mol respectively

Prattusha Chakraborty

7 Years agoGrade 12th pass

1 Answer

Arun

6 Years ago

Since heat is absorbed here at constant pressure so ΔH=1440 calories

ΔU can be calculated by using the formula ΔU=ΔH−PΔV

P=1atm, ΔV=0.0196L−0.180L=0.0016L

P ΔV=1∗0.0016=0.0016Latm=0.0016∗24.217calories. (1Latm=24.217 calories)

So ΔU=1440cal−0.0016∗24.217cal≈1439.96calories .There is negligible work done here.

so you can write ΔH≈ΔU.

In the reaction A + 2B ⇌ 2C, if 2 moles of A, 3 moles of B and 2 moles of C are placed in a 2 L flask and
the equilibrium concentration of C is 0.5 mol/L. The equilibrium constant (KC) for the reaction is.....and please tell how you know that the reaction is going forward .. imean how to calculate the reaction quotient ???

physical chemistry

5 Answers Available

Last Activity: 3 Months ago

Mc mukherjee physical chemistry jee solid state pdf

physical chemistry

1 Answer Available

Last Activity: 4 Months ago

These notes are really good for base on starting 11

physical chemistry

1 Answer Available

Last Activity: 5 Months ago

How do explain chemistry for understanding base tell me sir

physical chemistry

1 Answer Available

Last Activity: 5 Months ago

Come posso contattare TAP air portugal in Italia?-Tap Gruppo

physical chemistry

1 Answer Available

Last Activity: 5 Months ago

View all Questions