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`        Can I know the formula for work done in an adiabatic process in terms of only pressure ?`
2 years ago

```							Dear Shubham 	For an adiabatic process of ideal gas equation we have	     PVγ = K (Constant)               	Where γ is the ratio of specific heat (ordinary or molar) at constant pressure and at constant voluume	     γ = Cp/Cv	Suppose in an adiabatic process pressure and volume of a sample of gas changs from (P1, V1) to (P2, V2) then we have	     P1(V1)γ=P2(V2)γ=K 	Thus, P = K/Vγ	Work done by gas in this process is	     W = ∫PdV	where limits of integration goes from V1 to V2	Putting for P=K/Vγ, and integrating we get,	     W = (P1V1-P2V2)/(γ-1)         	In and adiabatic process if W>0 i.e., work is done by the gas then T21	If work is done on the gas (W2 > T1 i.e., temperature of gas rises.RegardsArun (askIITians forum expert)
```
2 years ago
```							you use this as well  W = (P1V1-P2V2)/(γ-1)  or   the work done in the adibatic process is   and we have another formula for work done in adibatic process in terms of temperature.     W = (P2V2-P1V1)/(1-γ)
```
2 years ago
```							Formula of work done by adiabatic process is W=nRT.where , n is number of moles.Which is equals to W= (p2v2-p1v1)/(1-y).
```
one year ago
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