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`        Calculate the value of dE and dH on heating 64.0 grams of oxygen from 273 k to 373 k . Cv and Cp on an average are 5 and 7 cal/mol/deg respectively`
one year ago

Shweta Ahire
44 Points
```							Delta E = heat(q) exchanged at constant volume So q= nCv deltaT        = 64/32 × 5 ×100    Delta  E =1000 cal =4.3 kJ  delta H = heat exchanged at constant pressure So q = nCp deltaT         =64/32 × 7 × 100      Delta H  = 1400 cal = 5.88kJ
```
one year ago
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• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions