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Calculate the total work done when one mole of a gas expands isothermally from an initial volume of 20dm³ to a final volume of 40dm³ at 298 K given R = 8.314 J / K mol
Work done is isothermal process is nRTln(V2/V1) = 1*8.314*298{ln(40/20)}so the work done is 1717.32 Jole the work done in volume increase will be +ve
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