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Calculate the temperature at which air possesses a density equal to that of hydrogen at 0'c. Density of air at ntp =14.4 Calculate the temperature at which air possesses a density equal to that of hydrogen at 0'c. Density of air at ntp =14.4
We know that, PV=nRTor, P= VMmRT= MM RTAt NTP, T=273KP is constantTherefore, ρ 1 T 1=ρ 2 T 2⇒16×273=14×T 2⇒T 2 =312K or 39° C (Ans.)
We know that, PV=nRT
or, P= VMm
RT= MM RT
At NTP, T=273K
P is constant
Therefore, ρ 1 T 1
=ρ 2 T 2
⇒16×273=14×T 2
⇒T 2 =312K or 39° C (Ans.)
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