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Grade: 12th pass
        Calculate  the most probable velocity of CO2 molecules at 27 degree celcius
2 years ago

Answers : (2)

Arun
23036 Points
							

molar mass

In case of oxygen gas, T = 27 + 273 = 300 K. R = 8.314 (kg m2 /s2 )/ K mol 

Since molar mass of oxygen gas O2 = 32 gm/mol = 3.2 x10-2 Kg/mol

Hence,  μ = (3RT/M)1/2 = [3 x8.314 x300 / 3.2 x10-2 ]1/2 = [233831.25 ]1/2 =483.56 m/s

Hence, the r.m. speed fro oxygen gas at O0C (273K) = 483.5 m/s

2 years ago
Rajat Gaikar
13 Points
							
For CO molar mass =12+16*2=44 g/mol=44*10-3 kg/mol
Vmp=(2RT/M)1/2=((2*8.314*300)/(44*10-3))1/2=336.70 m/s
one month ago
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