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molar mass
In case of oxygen gas, T = 27 + 273 = 300 K. R = 8.314 (kg m2 /s2 )/ K mol
Since molar mass of oxygen gas O2 = 32 gm/mol = 3.2 x10-2 Kg/mol
Hence, μ = (3RT/M)1/2 = [3 x8.314 x300 / 3.2 x10-2 ]1/2 = [233831.25 ]1/2 =483.56 m/s
Hence, the r.m. speed fro oxygen gas at O0C (273K) = 483.5 m/s
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