0

Guest

Courses New

Calculate the mass of Ethylene glycol which is required to prepare thousand Graham aqueous solution with a difference of 10 degree Celsius and its freezing point km equals to 1.86 degree Celsius kg per mole

Calculate the mass of Ethylene glycol which is required to prepare thousand Graham aqueous solution with a difference of 10 degree Celsius and its freezing point km equals to 1.86 degree Celsius kg per mole

Grade:12

1 Answers

Vikas TU
14149 Points
5 years ago
Freezing point depression formula is given as:
Tf = iKf*m
10  = 1*1.86*m
m = 5.37
moles = m*1000 => 5370
weight = 5370*molar mass
          = 5370*62
          = 332940 g

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More