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Calculate the hardness of water sample whose 10 ml required 20 ml of EDTA solution. 20 ml of CaCl2 solution whose strength is equivalent to 1.5 g of CaCO3 per litre, required 30 ml of EDTA solution

Calculate the hardness of water sample whose 10 ml required 20 ml of EDTA solution. 20 ml of CaCl2 solution whose strength is equivalent to 1.5 g of CaCO3 per litre, required 30 ml of EDTA solution

Grade:12th pass

4 Answers

Pawan Prajapati
askIITians Faculty 60787 Points
3 years ago
Answer ::

The standard water contains 1.5 g of CaCO3/l.
1000 ml of standard hard water (SHW), therefore, contain 15,00 mg of CaCO3.
1 ml of standard water = 15,00/1000 = 1.5 mg of CaCO3 equivalent.
10 ml of EDTA solution = 10 ml of SHW contains
=> 10* 1.5 = 15 mg of CaCO3 equivalent
1ml o EDTA Solution = 15 / 10 = 1.5 mg of CaCo3 equivalent
Calculation of hardness of water:
100 ml of water 30 ml of EDTA solution
30 * 1.5 = 45 mg of CaCO3 equivalent
1000 ml of water = 450 mg of CaCO3 equivalent
Hardness of water = 450 mg / l

Thanks
Tamilarasan
15 Points
3 years ago
1ml of cacl2=1.5  mg of caco3
30 ml of cacl2 =20 mg of caco3
20 ml of cacl2 = 20*1.5 =30 mg of caco3
1 ml of cacl2 =30/30 =1 mg of caco3
10 ml of sample water = 20 ml of edta
Total hardness,
Hardness=( 20/100)*1000
         =2000 ppm
irshad hussain
99 Points
2 years ago

he standard water contains 1.5 g of CaCO3/l.

1000 ml of standard hard water (SHW), therefore, contain 15,00 mg of CaCO3.

1 ml of standard water = 15,00/1000 = 1.5 mg of CaCO3 equivalent.

10 ml of EDTA solution = 10 ml of SHW contains

=> 10* 1.5 = 15 mg of CaCO3 equivalent

1ml o EDTA Solution = 15 / 10 = 1.5 mg of CaCo3 equivalent

Calculation of hardness of water:

100 ml of water 30 ml of EDTA solution

30 * 1.5 = 45 mg of CaCO3 equivalent

1000 ml of water = 450 mg of CaCO3 equivalent

Hardness of water = 450 mg / l

irshad hussain
99 Points
2 years ago

the standard water contains 1.5 g of CaCO3/l.

1000 ml of standard hard water (SHW), therefore, contain 15,00 mg of CaCO3.

1 ml of standard water = 15,00/1000 = 1.5 mg of CaCO3 equivalent.

10 ml of EDTA solution = 10 ml of SHW contains

=> 10* 1.5 = 15 mg of CaCO3 equivalent

1ml o EDTA Solution = 15 / 10 = 1.5 mg of CaCo3 equivalent

Calculation of hardness of water:

100 ml of water 30 ml of EDTA solution

30 * 1.5 = 45 mg of CaCO3 equivalent

1000 ml of water = 450 mg of CaCO3 equivalent

Hardness of water = 450 mg / l

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