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Calculate the hardness of water sample whose 10 ml required 20 ml of EDTA solution. 20 ml of CaCl2 solution whose strength is equivalent to 1.5 g of CaCO3 per litre, required 30 ml of EDTA solution Calculate the hardness of water sample whose 10 ml required 20 ml of EDTA solution. 20 ml of CaCl2 solution whose strength is equivalent to 1.5 g of CaCO3 per litre, required 30 ml of EDTA solution
Answer ::The standard water contains 1.5 g of CaCO3/l.1000 ml of standard hard water (SHW), therefore, contain 15,00 mg of CaCO3.1 ml of standard water = 15,00/1000 = 1.5 mg of CaCO3 equivalent.10 ml of EDTA solution = 10 ml of SHW contains=> 10* 1.5 = 15 mg of CaCO3 equivalent1ml o EDTA Solution = 15 / 10 = 1.5 mg of CaCo3 equivalentCalculation of hardness of water:100 ml of water 30 ml of EDTA solution30 * 1.5 = 45 mg of CaCO3 equivalent1000 ml of water = 450 mg of CaCO3 equivalentHardness of water = 450 mg / lThanks
1ml of cacl2=1.5 mg of caco330 ml of cacl2 =20 mg of caco320 ml of cacl2 = 20*1.5 =30 mg of caco31 ml of cacl2 =30/30 =1 mg of caco310 ml of sample water = 20 ml of edtaTotal hardness,Hardness=( 20/100)*1000 =2000 ppm
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