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`        Calculate the freezing point depression expected for 0.0755 m aqueous solution of Na2SO4. If this solution actually freezes at –0.480°C, what would be the value of van’t Hoff factor? (Kf for water = 1.75 K kg/mol).`
2 years ago

Patel priyanka
20 Points
```							Dispersion in freezing point, expected∆Tf=T°-Tf=Kfmm=0.0755m, kf=1.75 K kg/mol ,∆Tf=1.75×0.0755=0.132℃If TF=-0.480℃Then ,∆Tf=0.480℃=iKfm                                0.480 =i1.75x0.0755                                i=1.75×0.0755÷0.480                               i=0.00027
```
2 years ago
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