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calculate PH of a solution whose 100 mL contains 0.2 g NaOH dissolved in it
Moles of NaOH =0.2/40=0.005Hence moles of OH¯=0.005Concentration of OH¯=0.005/0.1=0.05pOH=-log(0.05)1.30pH=14-1.3pH=12.7
Molecular maa of NaOH=40Since given 0.2 gm of NaOH is dissolved in a solution of 100 mlThen,moles of NaOH =0.2/40=0.005=5×10-3moles of OH -=5×10-3concentration ofOH-=5×10-3/0.1=5×10-2pOH=-log(5×10-2)=1.30As we know ,pH+pOH=14Then,pH=14-1.30=12.7
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