badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

Bond energy of H—H, F-F and H-F bonds are 104, 38 and 135 kcal mol-respectively. The resonance energy in the H-F molecule will be ...... kcal mol"? I got answer but didn't understand that how we put square root in solution. How that formula is generated?

6 months ago

Answers : (2)

Saurabh Koranglekar
askIITians Faculty
8407 Points
							576-454_IMG_20200414_183746.jpg
						
6 months ago
Vikas TU
12278 Points
							
Dear student 
Resonance energy = delH - F = (BE)H-F - sqrt((BE)H2*(BE)F2)
Resonance energy = 135 – sqrt (104 * 38)
 
 = 135 – 62.86
 = 72.14 KCal/mol
Good Luck
6 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details