Create your Smart Home App in the Free Webinar on Home Automation. Register Now
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Free webinar on App Development Learn to create your own Smart Home App
16th Jan @ 5:00PM for Grade 1 to 10
Sit and relax as our customer representative will contact you within 1 business day
At what temperature will the r.m.s. velocity of oxygen be one and half times of its value at N.T.P.? Solution: 1/2 mc 2 = 3/2 KT Suppose the temperature required is T¢ when the velocity will be 3/2 C 3/2C / C = √T'/T or, T' = 9/4 × 273 = 614.25°K Plzzź explain solution or use any other method i dont understand the way they solved it
Dear Azhar, As we knowE = 1/2 m* c²Also E = 3/2 *K* TNow1/2 * m * c² = 3/2* K*TNow C² is proportional to TC is proportional to THenceC1/C2 = (T1/T2)1/2But C1 = 3/2 * CC2 = CHence3/2 = (T1/273)1/2T1 = 273 *9/4 = 614.25 K Hope it helps Regards,Arun ( AskIITians forum Expert)
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -