Nishakar kumar
Last Activity: 7 Years ago
CO + Cl2 = CoCl2 2. 3. 0. (At t=0) 2-x. 3-x. x. (At equilibrium)As mentioned in the Q...At equilibrium 1 mole of CO is present therefore...2-x = 1X=1Now... Substituting the value of x we get..At equilibrium...1 mole of CO (1/5). |2 moles of Cl2 (2/5). | (There conc.)1 mole of COCl2 (1/5). |Kc = (1/5) ÷ (2/5)(1/5)= 2.5