Sunil Kumar FP
Last Activity: 10 Years ago
pi1=c1RT
pi2=C2RT
Pi1/pi2=C1/C2
Let us calculate the concentration of the first solution with osmotic pressure of 4.98 bar:
Mass of glucose = 36 g
Molar mass of glucose = 180 g/mol
Number of moles of glucose = 36/180 = 0.2 moles Volume of the solution = 1 L Molarity = Number of moles of glucose / Volume of the solution
Molarity = 0.2 moles / L π1= 4.98 bar π1= 1.52 bar C2=1.52*.2/4.98